Question

What is the equation of the circle with center (4. -4) that passes through the point (1, 0)?
(x - 4)2 + (y + 4)2 = 25
(x-4)2 + y - 4)2 = 25
(x+4)2 + (y + 4)2 = 5
(x-4)²-(y + 4)² = 25

Answer 1

Correct answer: A

equation of a circle having a centre (4, -4):

(x-4)² + (y+4)² =r²

now, (1, 0) passes through the circle.

Then, (1-4)² + (0+4)² =r²

So,  9 + 16 =r² =25

(x-4)² + (y+4)² =25