Respuesta :
Answer:
The height of the flag pole will be = 18.96 ft.
Step-by-step explanation:
See the attached diagram.
AB is the flag pole and the length of the shadow is AC.
Now, Δ ABC is a right triangle and has AB = 3x ft., BC = 20 ft. and AC = x ft.
So, applying Pythagoras theorem ,
AB² + AC² = BC²
⇒ (3x)² + x² = 20²
⇒ 10x² = 400
⇒ x² = 40
⇒ x = 6.32 ft. (Approx.)
So, the height of the flag pole will be = 3x = 3 × 6.32 = 18.96 ft. (Answer)

Answer:
The height of the flag pole = [tex]6\sqrt{10} feet[/tex]
Step-by-step explanation:
Let us consider, the length of the shadow = x
According to the question,
The length of the flag pole = 3 times length of the shadow.
= 3x
From the figure, By "Pythagoras theorem",
[tex]x^{2} + (3x)^{2} = 20^{2}\\[/tex]
[tex]x^{2} + 9x^{2} = 400[/tex]
[tex]10x^{2} = 400\\ x^{2} = 40\\ x = \sqrt{40} \\ x = 2\sqrt{10}[/tex]
So, The length of flag pole = [tex]3\times x[/tex]
= [tex]3\times2\sqrt{10} = 6\sqrt{10} feet[/tex]
