Answer:
V₂ = 19.3 L
Explanation:
Given data:
Initial volume = 29.3 L
Initial pressure = standard = 1 atm
Initial temperature = standard = 273 K
Final temperature = -23°C (-23+273 = 250K)
Final volume = ?
Final pressure = 1.39 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
V₂ = P₁V₁ T₂/ T₁ P₂
V₂ = 1 atm × 29.3 L × 250 K / 273 K × 1.39 atm
V₂ = 7325 atm .L. K / 379.47 K.atm
V₂ = 19.3 L
