Answer:
temperature for which two scales are same is given as
[tex]x = - 40^oC[/tex]
Explanation:
As we know that temperature scales are linear function
so we can compare two temperature scales by
[tex]\frac{T_c - T_f}{T_b - T_f} = constant[/tex]
now we have
[tex]\frac{T_c - 0}{100 - 0} = \frac{T_f - 32}{212 - 32}[/tex]
here we know that
[tex]T_c = T_f = x[/tex]
so we have
[tex]\frac{x - 0}{100} = \frac{x - 32}{180}[/tex]
[tex]1.8 x = x - 32[/tex]
[tex]x = - 40^oC[/tex]