Given:
Volume of water in each container.
To find:
Difference in the rate of change.
Solution:
Take any two points on container 1.
Let the points are (10, 2) and (20, 4).
[tex]$m=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]$m=\frac{4-2}{20-10}[/tex]
[tex]$m=\frac{2}{10}[/tex]
[tex]$m=\frac{1}{5}[/tex]
Rate of change for container 1 is [tex]\frac{1}{5}[/tex].
Take any two points on container 2.
Let the points are (5, 2) and (10, 4).
[tex]$m=\frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]$m=\frac{4-2}{10-5}[/tex]
[tex]$m=\frac{2}{5}[/tex]
Rate of change for container 2 is [tex]\frac{2}{5}[/tex].
Difference = [tex]\frac{2}{5}-\frac{1}{5}[/tex]
[tex]$=\frac{1}{5}[/tex]
The difference in the rate of change between the two containers is [tex]\frac{1}{5}[/tex] gallon per minute.