can someone help me?

Answer:
A
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Calculate m using the slope formula
m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]
with (x₁, y₁ ) = (- 2, 0) and (x₂, y₂ ) = (0, 4) ← 2 points on the line
m = [tex]\frac{4-0}{0+2}[/tex] = [tex]\frac{4}{2}[/tex] = 2
Note the line crosses the y- axis at (0, 4) ⇒ c = 4
y = 2x + 4 → A
Answer:
A. y = 2x + 4
Step-by-step explanation:
We need to find the equation of the line in slop-intercept form. This is written as y = mx + b. Let m represent the slope and b represent the y intercept.
First lets find the slope. We can do this by finding rise/run.
Two points on the graph:
(0, 4) and (3, 10)
We'll set up the formula like this:
(y2 - y1) ÷ (x2 - x1)
(10 - 4) ÷ (3 - 0)
6 ÷ 3
= 2
This means the slope (m) is 2.
Now we'll find the y-intercept. This is the point where the line crosses the y-axis. If we look at the graph, this is at (0, 4).
This means the y-intercept (b) is 4.
Now plug the values into the equation:
y = mx + b
y = 2x + 4
This is the equation, so the answer is A!