Question

Which formula equation represents the burning of sulfur to produce sulfur dioxide?
a. $S (s) + O_2 (g) \overset{\Delta}{\rightarrow} SO_2 (g).$b. $2H_2S (s) + 3O_2 (g) \rightarrow 2H_2O (l) + 2SO_2 (g).$c. $4FeS_2 + 11O_2 \rightarrow 2Fe_2O_3 + 8SO_2.$d. $2SO_2 (g) + O_2 (g) \overset{V_2O_ 5}{\longrightarrow} 2SO_3 (g).$

Answer 1

Answer:

The answer to your question is the letter a.

Explanation:

The symbol of sulfur is S

Burning means that the element or molecule will react with Oxygen (O₂)

Analysis of the reactions given

a) This is the right answer because the reactants are sulfur and oxygen.

b) This option is incorrect because the reactants are hydrosulfuric acid and oxygen.

c) This option is also incorrect because one of the reactants is Iron sulfide.

d) This option is also incorrect because one of the reactants is sulfur oxide.

Answer 2

Answer:

The correct equation is the first one

S(s) + O2(g) → SO2(g)

Explanation:

Step 1: Data given

Sulfur = S

combustion reaction = adding O2

sulfur dioxide = SO2

Step 2: The unbalanced equation

S(s) + O2(g) → SO2(g)

This equation is already balanced.

2H2S + 3O2 → 2H2O + 2SO2

In this reaction sulfur dioxide is generated. But the reactants are Hydrogen sulfide (H2S) and oxygen gas (O2)

4FeS2 + 11O2 → 2Fe2O3 + 8SO2

In this reaction sulfur dioxide is generated. But the reactants are Ferrous disulfide (Fe2) and oxygen gas (O2)

2SO2 + O2 → 2SO3

In this reaction sulfur dioxide is the reactant. The combustion of sulfur dioxide will give sulfur trioxide.

The correct equation is the first one

S(s) + O2(g) → SO2(g)