Answer: The time time taken for the sample to decay from [tex]4.4\times 10^2g[/tex] to [tex]1.0\times 10^2[/tex] is [tex]5.29\times 10^5years[/tex]
Explanation:
Expression for rate law for first order kinetics is given by:
[tex]t=\frac{2.303}{k}\log\frac{a}{a-x}[/tex]
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) for completion of half life:
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
[tex]t_{\frac{1}{2}}=\frac{0.693}{k}[/tex]
[tex]k=\frac{0.693}{2.44\times 10^5year}=0.28\times 10^{-5}year^{-1}[/tex]
b) time taken for the sample to decay from [tex]4.4\times 10^2g[/tex] to [tex]1.0\times 10^2[/tex]
[tex]t=\frac{2.303}{0.28\times 10^{-5}}\log\frac{4.4\times 10^2}{1.0\times 10^2}[/tex]
[tex]t=5.29\times 10^5years[/tex]
The time time taken for the sample to decay from [tex]4.4\times 10^2g[/tex] to [tex]1.0\times 10^2[/tex] is [tex]5.29\times 10^5years[/tex]