Question

What is the sum of a 29-term arithmetic sequence where the first term is 180 and the
last term is -16?

Answer 1

Answer:

Answer is 2378

Step-by-step explanation:

$sn = \frac{n}{2} (a + l) \\ here \: n = 29 \: \: a = 180 \: \: l = - 16 \\ s29 = \frac{29}{2} (180 - 16) \\ = \frac{29}{2} \times 164 \\ = 29 \times 82 \\ = 2378$

sum to 29 terms is 2378

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