Answer:
3.84 g HBr
Explanation:
A reaction between Propene and HBr is given by the equation;
HBr + C₃H₆ → C₃H₇Br
Note; this is an addition reaction where hydrogen halides are added to an alkene.
We are given 2 g of propene
Required to determine the mass of HBr used;
We first determine the number of moles of propene used
Moles = Mass ÷ molar mass
Molar mass of propene = 42.08 g/mol
Therefore;
Moles of propene = 2 g ÷ 42.08 g/mol
= 0.0475 moles
Then, from the equation, 1 mole of HBr reacts with 1 mole of propene
Thus;
Moles of HBr = Moles of propene
Moles of HBr = 0.0475 moles
Lastly, we determine the mass of HBr
Mass = Moles × Molar mass
Molar mass of HBr = 80.91 g/mol
Therefore;
Mass of HBr = 0.0475 moles × 80.91 g/mol
= 3.84 g
