Question

Ungle Jim runs along level ground at 5 m/s. He grabs a vine and swings up to the edge of a nearby cliff (above the level ground on which he was running), just making it to the height of thecliff, essentially at rest. He then steps off onto the cliff.1. How high is the cliff above the level ground?

Answer 1

Answer:

1.276 m

Explanation:

According to the law of conservation of energy,

The potential energy at the top of the cliff = kinetic energy at the bottom of the cliff.

Potential energy at the top of the cliff = mgh

Kinetic energy at its bottom = (1/2)mv²

where m = mass of the man

g = acceleration due to gravity = 9.8 m/s²

h = height of the cliff

v = velocity at the bottom of the cliff

mgh = (1/2)mv²

h = (v²/2g)

h = [5²/(2×9.8)]

h = 1.276 m

Hope this Helps!!!

Answer 2

Answer:

Maximum Height = 1.274m

Explanation:

The maximum Kinetic energy of Ungle Jim at the swing = Maximum potential energy at the swing

Kinectic Energy = Potential Energy

1/2mv² = mgh

Therefore,

The maximum height = v²÷ 2g

v = speed of Ungle jim

Where g = acceleration due to gravity = 9.81 m/s²

Maximum height = (5 m/s²) ÷ (2 × 9.81 m/s²)

= 1.274m