Question

Find the value of x
in the isosceles triangle shown

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Answer 1

Given that the isosceles triangle has sides √45, √45 and x.

The triangle has a height of 3 units.

We need to determine the value of x.

Value of x:

The value of x can be determined using the formula,

$b=2\sqrt{a^2-h^2}$

Where b is the base of the triangle, a is the sides of the isosceles triangle and h is the height of the triangle.

Substituting $a=\sqrt{45}$ , $b=x$ and $h=3$ in the above formula, we get;

$x=2\sqrt{(\sqrt45)^2-(3)^2}$

Squaring the terms, we have;

$x=2\sqrt{45-9}$

Subtracting, we get;

$x=2\sqrt{36}$

$x=2(6)$

$x=12$

Thus, the value of x is 12

Hence, Option B is the correct answer.