The two values of x are -6.77 and 4.27
Explanation:
Given:
2x² + 5x - 58 = 0
Solving the equation further:
For quadratic equation:
[tex]x = -b +- \frac{\sqrt{b^2-4ac} }{2a}[/tex]
where,
a = 2
b = 5
c = -58
Substituting the values in the equation we get:
[tex]x = -5 + \frac{\sqrt{5^2-4X2X-58} }{2 X 2} \\\\x = -5 +- \frac{\sqrt{489} }{4} \\\\x = 4.27, -6.77[/tex]
The two values of x are -6.77 and 4.27
