Question

How much energy is needed to heat 1 kg of sand, which has a specific heat of 664 J/(kg K), from 30°C to 50°C?

Answer 1

Answer:

Q = nC∆T

here Q = energy required

n = amount of substance

C = specific heat

then

Q = 1×664×(50-30) = 13280 j Answer

Answer 2

The energy  needed to heat 1 kg of sand under the conditions listed in the

question is 13,280J.

We can calculate the energy by using the formula shown below

Q = nC∆T

where  Q is energy required, n is the amount , c is specific heat and ∆T is temperature change.

This can be calculated by substituting the variables into the equation.

Q = 1×664×(50-30)

  = 664 × 20

  = 13,280J

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