Question

11. The following chemical equation shows the reaction between iron and chlorine.
2Fe + 3C12 --> 2FeCl3
1.12g of iron burns completely in chlorine. What is the mass of the product?
[Relative atomic mass: CI=35.5, Fe=56] *
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Answer 1

Answer:

3.25g

Explanation:

2Fe + 3C12 —> 2FeCl3

Molar Mass of Fe = 56g/mol

Mass of Fe from the balanced equation = 2 x 56 = 112g

Molar Mass of FeCl3 = 56 + (3 x 35.5) = 56 + 106.5 = 162.5g/mol

Mass of FeCl3 from the balanced equation = 2 x 162.5 = 325g

The mass of the product formed can be obtained by doing the following:

From the equation above,

112g of Fe burns in chlorine to produced 325g of FeCl3.

Therefore, 1.12g of Fe will burn in chlorine to produce = (1.12x325)/112 = 3.25g of FeCl3.

Therefore, 3.25g of the product (FeCl3) are produced.