Question

factor completely:
4x²-49=

Answer 1

$4x^2-49$

Use the Difference of Two Squares Formula, $x^2-y^2=(x+y)(x-y)$

If x² = 4x², then x = √4x², x = 2x

If y² = 49, then y = √49, y = 7

We know both x and y, straight to formula.

$x^2-y^2=(x+y)(x-y)\\4x^2-49=(2x+7)(2x-7)$

Therefore, the factored form of 4x²-49 is (2x+7)(2x-7)