Question

Solve the system of equations 3x + y = 3 and 7x + 2y = 1.

Answer 1

Step-by-step explanation:

3x+y = 3.........equation 1

7x+2y = 1.........equation 2

Multiplying equation 1 by 2 and Solving both

6x+2y = 6

7x+2y =1

- - -

-x = 5

Therefore x = -5

Putting x= -5 in equation 1

3 * -5 +y = 3

-15 + y = 3

y = 3+15

therefore y = 18

Hope it helped

Answer 2

Answer:

$x=-5\\y=18$

Step-by-step explanation:

Given equations:

$3x + y = 3$   Equation:1

$7x + 2y = 1$  Equation:2

Multiplying Equation:1 by '2'

$6x+2y=6$    Equation:3

Using elimination method:

 Subtract Equation:3 from Equation:2:

$7x+2y-(6x+2y)=1-6\\\\7x+2y-6x-2y=-5$

Solving the like terms:

$7x-6x=-5\\\\x=-5$

Putting the value of 'x' in Equation:1

$3x + y = 3$

$3(-5) + y = 3\\\\-15+y=3$

Adding '15' both sides:

$y=3+15\\\\y=18$

The solution of the equations is:

$x=-5\\y=18$