Answer:
22.5L will be the new volume for the gas
Explanation:
Pressure and number of moles remains constant.
When the temperature for a sample of gas is increased, the volume will also be increased, acording to this relation:
V₁ / T₁ = V₂ / T₂
15L / 30°C = V₂ / 45°C
(15L / 30°C ). 45°C = 22.5L
We assume Ar, as an Ideal Gas
Answer:
When the temperature increases with 15 °C the new volume will be 15.7 L
Explanation:
Step 1: Data given
Initial volume of the neon = 15.0 L
Initial temperature of the neon = 30.0 °C = 303 K
The temperature is increased by 15°C = 318 K
Step 2: Calculate the new volume
V1/T1 = V2/T2
⇒with V1 = the initial volume of neon = 15.0 L
⇒with T1 = the initial temperature = 303 K
⇒with V2 = the final volume = TO BE DETERMINED
⇒with T2 = the increased temperature = 318 K
15.0 L / 303 K = V2 / 318 K
V2 = (15.0 L/ 303 K) * 318 K
V2 = 15.7 L
When the temperature increases with 15 °C the new volume will be 15.7 L
