Question

A 3200 kg police car traveling North at 40 m/s collides with another car also traveling North. The second car has a mass of 2000 kg and its velocity is 30 m/s North just before the collision. If the cars stick together on contact what will be their common velocity just after collision? Neglect the effect of friction from the road.

Answer 1

Explanation:

we are to use the law of momentum

where by total momentum before collision is equal to total momentum after collision hence m1u1+m2u2 =V(M1+M2)

(3200×40)+(2000×30)=V(3200+2000)

128000+60000=V(5200)

188000=5200V

188000÷5200=5200V÷5200

V=36.154m/s