Question

To assess whether your calculations make sense, let's simplify the problem even further and assume air resistance is negligible. In this case, the net force acting on the bicyclist is equivalent to just the force of static friction, and your answer to Part D is the magnitude fsfsf_s. Based on this value, what is the minimum coefficient of static friction μsμsmu_s between the race track and the bicycle?

Answer 1

Complete Question

The complete question is shown on the first uploaded image

Answer:

the minimum coefficient of static friction is  $\mu_s = 0.63$

Explanation:

From the Question we are given that

                      The force of static friction(i.e the net force ) is $F_s = 467.88N$

                       The normal force is $N = mg$

where m is the mass = 76 Kg  and

           g is the acceleration due to gravity

             Now the minimum coefficient of static is friction is mathematically represented as

           $\mu_s = \frac{F_s}{N}$

Substituting mg for N

         $\mu_s = \frac{F_s}{mg}$

Substituting values

           $\mu_s = \frac{467.88}{76 * 10}$

                $= 0.63$