Answer:
163.2 g of Li₃PO₄ are made in the reaction
Explanation:
In first place we determine the reaction, to see stoichiometry.
The reactants are Li and Pb₃(PO₄)₂; the products are Li₃PO₄ and Pb
Equation: 6Li + Pb₃(PO₄)₂ → 2Li₃PO₄ + 3Pb
6 moles of Li can produce 2 moles of lithium phosphate
Therefore, 4.22 moles of Li will produce (4.22 . 2) / 6 = 1.41 moles of Li₃PO₄
Let's convert the amount to mass, to find the answer:
1.41 mol . 115.79 g / 1mol = 163.2 g
