25 points PLEASE HELP NOW
DUE TODAY
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Answer:
440
Step-by-step explanation:
Her we have two objects: 2 square.
1st has dimension 5x5x8
2nd has dimension 10x10x2
But we also have invisible prarts, the bottom of 1st is on the top od the 2nd. So we will remove something.
The formula for the surface of the square is
S=2B+M
Surface area of the first is
S1=2x5x5+4x8x5=50+160=210
Surface are of the 2nd is
S2=2x10x10+4x10x2=200+80=280
S=s1+s2-50=210+280-50=440
This -50 is are od one base from first square 5x5=25 whic we added in s1, but in real it is invisible.
The same area we added in s2. The top is 10x10-5x5 (invisible prat).
So we added two times 25, it is 50.
Answer: surface area = 440 in²
Step-by-step explanation:
The given solid is made up of two cuboids. The formula for determining the surface area of a cuboid is expressed as
Surface area = 2lw + 2lh + 2wh
Where
l, w and h are the length, width and height of the cuboid.
Considering the cuboid at the top, its base will not be added. Therefore, the surface area would be
lw + 2lh + 2wh
= 5 × 5 + 2(8 × 5) + 2(8 × 5)
= 25 + 80 + 80
= 185 in²
Considering the box at the base, we would determine the surface area and subtract the area of the base of the first box.
Surface area of bottom box is
2(10 × 10) + 2(10 × 2) + 2(10 × 2)
= 200 + 40 + 40 = 280 in²
The area of the base of the first box is 5 × 5 = 25 in²
Surface area of the bottom box is 280 - 25 = 255 in²
Total surface area of the design is
Area of first box + area of second box
= 185 + 255 = 440 in²