Question

a bus travels 4 km due north and 3 km due west going from bus station a to bus station b. the magnitude of the bus displacement from station a to station b is what km

Answer 1

Answer:

5km

Explanation:

Magnitude of displacement is found by getting the resultant. Resultant is same as the bypotenuse hence

$R=\sqrt {{x^{2}+y^{2}}$ where x is the displacement in west direction and y is displacement in North direction. Substituting x with 3km and y with 4 km then

$R=\sqrt {{3^{2}+4^{2}}=5km$