Segment NO is parallel to the segment KL.
Solution:
Given KLM is a triangle.
MN = NK and MO = OL
It clearly shows that NO is the mid-segment of ΔKLM.
By mid-segment theorem,
The segment connecting two points of the triangle is parallel to the third side and is half of that side.
⇒ NO || KL and [tex]NO = \frac{1}{2}KL[/tex]
Therefore segment NO is parallel to the segment KL.
