For this case we have:
Diana:
[tex]\frac {3} {8}[/tex] mile in 5 minutes.
To find the speed we divide the distance by the time:
[tex]v = \frac {\frac {3} {8}} {5} = \frac {3} {40} = 0.075 \frac {mile} {min}[/tex]
Thus, Diana's speed is [tex]0.075 \frac {mile} {min}[/tex]
Fernando:
[tex]2 \frac {1} {2} = \frac {5} {2}[/tex]mile in [tex]\frac {3} {4}[/tex]
[tex]v = \frac {\frac {5} {2}} {\frac {3} {4}} = \frac {4 * 5} {2 * 3} = \frac {20} {6} = 3.33 \frac {mile} {min}[/tex]
Thus, Fernando's speed is[tex]3.33 \frac {mile} {min}[/tex]
We find the speed in miles per hour considering that an hour has 60 minutes.
Diana:
[tex]0.075 \frac {mile} {min} * \frac {60} {1} \frac {min} {h} = 4.5 \frac {mile} {h}[/tex]
Fernando:
[tex]3.33 \frac {mile} {min} * \frac {60} {1} \frac {min} {h} = 199.8 \frac {mile} {h}[/tex]
Answer:
Diana's speed is [tex]0.075 \frac {mile} {min} = 4.5 \frac {mile} {h}[/tex]
Fernando's speed is [tex]3.33 \frac {mile} {min} = 199.8 \frac {mile} {h}[/tex]
