Question

This equation shows how the distance Tess runs depends on the number of track practices she attends.

d = p + 8

The variable p represents the number of track team practices she attends, and the variable d represents the distance run in miles. How many track practices would it take for Tess to run 11 miles?

practices

Answer 1

Answer:

$3\ track\ practices$

Step-by-step explanation:

Let

d ----> distance Tess runs in miles

p ---> the number of track practices she attends

we have

$d=p+8$

This is a linear equation in slope intercept form

where

The slope or unit rate is

$m=1\ mile/track$

The y-intercept (value of d when the value of p is equal to zero) is

$b=8\ miles$

so

For d=11 miles

substitute in the linear equation and solve for p

$11=p+8$

solve for p

$p=11-8\\p=3\ track\ practices$