Answer:
After 20 months
Step-by-step explanation:
This is a compound growth problem which has the formula:
[tex]F=P(1+r)^t[/tex]
Where
F is future value
P is present amount
r is the rate of growth
t is the time (in months)
Future amount is $65, what he needs at-least
P is the initial amount, that is $10
r is the rate of growth, which is 10% or 10/100 = 0.1
t is time in months, what we need to find
Substituting and solving we get:
[tex]F=P(1+r)^t\\65=10(1+0.1)^t\\65=10(1.1)^t\\6.5=1.1^t\\ln(6.5)=ln(1.1^t)\\ln(6.5)=t*ln(1.1)\\t=\frac{ln(6.5)}{ln(1.1)}\\t=19.64[/tex]
He would need 19.64 months to save up at-least 65. So, that means, he would need 20 months