Answer:
x = [tex]\sqrt{13}[/tex]
Step-by-step explanation:
The line from the vertex to the base is a perpendicular bisector and divides the triangle into 2 right triangles.
Consider the right triangle on the left with base 2
Using Pythagoras' identity
The square on the hypotenuse (x) is equal to the sum of the squares on the other 2 sides, that is
x² = 2² + 3² = 4 + 9 = 13 ( take the square root of both sides )
x = [tex]\sqrt{13}[/tex]
