Your car's 30.0 W headlight and 2.50 kW starter are ordinarily connected in parallel in a 12.0 V system. What power (in W) would one headlight and the starter consume if connected in series to a 12.0 V battery

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Answer:

The power of headlight in series connection is 29.64 W

Explanation:

Given :

Power of headlight [tex]P_{1} = 30[/tex] W

Power of starter [tex]P_{2} = 2500[/tex] W

Voltage of headlight and starter [tex]V = 12[/tex] V

From equation of power,

 [tex]P = \frac{V^{2} }{R}[/tex]

 [tex]R = \frac{V^{2} }{P}[/tex]

For finding the resistance of headlight and starter,

⇒ For headlight,

 [tex]R_{1} = \frac{144}{30} = 4.8[/tex] Ω

⇒ For starter,

[tex]R_{2} = \frac{144}{2500} = 0.057[/tex] Ω

Since equivalent resistance,

[tex]R_{eq} = R_{1} + R_{2} + ........[/tex]

[tex]R_{eq} = 4.8 +0.057 = 4.857[/tex] Ω

So power in series is given by,

 [tex]P_{s } = \frac{V^{2} }{R_{eq} } = \frac{144}{4.857}[/tex]

 [tex]P_{s } = 29.64[/tex] W

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