Respuesta :
Answer:
a) In 32.82% this portfolio lose money, i.e. have a return less than 0%
b) The cutoff for the highest 15% of annual returns with this portfolio is an annual return of 48.86%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
[tex]\mu = 0.147 \sigma = 0.33[/tex]
a.) What percent of years does this portfolio lose money, i.e. have a return less than 0%
This is the pvalue of Z when X = 0. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{0 - 0.147}{0.33}[/tex]
[tex]Z = -0.445[/tex]
[tex]Z = -0.445[/tex] has a pvalue of 0.3282
In 32.82% this portfolio lose money, i.e. have a return less than 0%
b.) What is the cutoff for the highest 15% of annual returns with this portfolio"
This is X when Z has a pvalue of 1-0.15 = 0.85. So it is X when Z = 1.035.
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]1.035 = \frac{X - 0.147}{0.33}[/tex]
[tex]X - 0.147 = 0.33*1.035[/tex]
[tex]X = 0.4886[/tex]
The cutoff for the highest 15% of annual returns with this portfolio is an annual return of 48.86%.