Question

Point P' is the image of P(6,0) under the translation
(x,y) → (x – 6, y - 1).
What are the coordinates of P'?

Answer 1

Answer:

P' = (0, -1)

Step-by-step explanation:

Step 1:  Send point P through the translation

P' = (x - 6, y - 1)

P' = ((6) - 6, (0) - 1)

P' = (0, -1)

Answer:  P' = (0, -1)

Answer 2

Answer:

Step-by-step explanation: