Question

How much energy must be added to a 2-kg piece of aluminum with a specific
heat of 900 J/(kg°C) to increase its temperature from 10°C to 50°C?
O
A. 1,800 J
O B. 900,000 J
O C. 108,000 J
O D. 72,000 J

Answer 1

Answer: 72,000 Joules

Explanation:

Heat Energy Q = Mass M x Specific heat capacity C x change in temperature Φ

Thus, Q = MCΦ

Then, M = 2-kg

C = 900 J/(kg°C)

Φ = 50°C - 10°C = 40°C

Q = 2 x 900 x 40

Q= 72,000 Joules

Thus, it takes 72,000 Joules of energy