Answer:
Explanation:
a. The optimal order size
Qopt = root of 2*Co*D/Cc(1-d/p)
Co - Setup sost, $1600
D - Demand, 10000
Cc - Carrying cost, $15/log
p - production rate, 60logs/day
d - inventory demand rate = Demand/days = 10,000/250 = 40logs/day
Qopt = root of 2*1600*10000/15*(1-40/60) = root of 32,000,000/4.95 = 2543logs
b. The total inventory cost associated with the optimal order quantity
TC = Co*D/Qopt + [Cc*Qopt/2 ] *(1 - d/p)
TC = 1600*10000/2543 + [15*2543/2] *(1-40/60) = 6291.78 + 6293.76 = 12585.54
c. The number of operating days between orders
N = D/Qopt
N = 10000/2543 = 4 (optimal number of orders per year)
T = Days/N = 250/4 = 62.5 days