Question

Determine the concentration of a 1.00 M solution of sodium chloride (NaCl) after the following changes occur. (a) Exactly one liter of the solution is mixed with 0.40 L of water.

Answer 1

Answer: 0.714 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

According to the neutralization law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of stock  solution = 1.00 M

$V_1$ = volume of stock  solution = 1.00 L

$M_2$ = molarity of dilute  solution = ?

$V_2$ = volume of dilute  solution = (1.00+0.40) L = 1.40 L

$1.00\times 1.00=M_2\times 1.40$

$M_2=0.714M$

The concentration of a 1.00 M solution of sodium chloride (NaCl) after exactly one liter of the solution is mixed with 0.40 L of water is 0.714 M