For each of the described curves, decide if the curve would be more easily given by a polar equation or a Cartesian equation. Then write an equation for the curve.
(a) A line through the origin that makes an angle of π/3 with the positive x-axis.
(b) A vertical line through the point (4, 4).

Respuesta :

Answer:

a) [tex]y=\sqrt{3}\ (x)[/tex] is the equation of the curve that makes an angle π/3.

b) [tex]x=3[/tex] is the equation of line through the point (4,4).

Step-by-step explanation:

Given:

A line from origin which makes an angle of [tex]\frac{\pi }{3}[/tex] with x-axis.

A vertical line from [tex](4,4)[/tex] .

We have to write the equation of the curves in Polar or Cartesian format.

Step wise:

a) A line from origin which makes an angle of [tex]\frac{\pi }{3}[/tex] with x-axis.

To write the equation of the above line in Polar coordinates is more desirable as the angles could be defined well in polar form.

So,

⇒ [tex]y=mx[/tex] ...equation (i)

⇒ [tex]m=\frac{y}{x}[/tex]...here [tex]m[/tex] is the slope

The slope in terms of [tex]\theta[/tex] (angle) can be written as,

⇒ [tex]tan(\theta)=\frac{y}{x}[/tex]

Plugging the values of the angle,[tex]\theta =\frac{\pi }{3}[/tex] .

⇒ [tex]tan(\theta) =\frac{\pi}{3} = \sqrt{3}[/tex] ...equation (ii)

Now re-arranging the equation (i) we can write it as,

⇒  [tex]y=\sqrt{3}\ (x)[/tex]

b) A vertical line from [tex](4,4)[/tex] .

Note:

The equation of a vertical line always takes the form x = k, where k is any number and k is also the x-intercept .

To write the above point in Cartesian coordinate is more acceptable and easy for us.

⇒ [tex]x=4[/tex]

Then,

y = sq-rt(3) x is the equation of the curve that makes an angle π/3.

and x = 3 is the equation of line through the point (4,4).

Answer:y = sq-rt(3) x is the equation of the curve that makes an angle π/3.

and x = 3 is the equation of line through the point (4,4)

Step-by-step explanation:

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