Respuesta :
Answer:
4 bags of crackers and 8 bags of pretzels.
Step-by-step explanation:
Let number of crackers=c
Let number of pretzels=p
Tim is buying snacks for 12 people and each person gets only one snacks. Therefore:
c+p=12. (Equation 1)
Bags of pretzels costs $1.50 per bag.
Bags of crackers that cost $2.00 per bag.
Tim has $20 to buy snacks.
1.50p+2c=20. (Equation 2)
We then solve the two equations to find out how many bag of each type of snacks can be bought.
c+p=12.
1.50p+2c=20
From Equation (1), c=12-p
Substitute c=12-p into equation (2).
1.50p+2(12-p)=20
Opening the bracket
1.50p+24-2p=20
Next, I collect like terms
1.50p-2p=20-24
-0.5p=-4
Divide both sides by -0.5 to solve for p.
p=8.
Recall from Equation 1.
c=12-p =12-8=4
Therefore, Tim can get 4 bags of crackers and 8 bags of pretzels.
Answer:
Step-by-step explanation:
Given:
Total amount = $20
Cost:
1 bag of pretzel = $1.50
1 bag of crackers = $2.00
Let the number of bag of pretzel be x and number of bag of crackers be y.
Total number of people = 12
Total number of people = x + y
1. x + y = 12
Total cost = $20
Total cost = 1.5x + 2y
2. 1.5x + 2y = 20
Solving equarion 1 and 2 simultaneously,
x = 12 - y into equation 2,
1.5(12 - y) + 2y = 20
0.5y = 20 - 18
y = 4
x = 8
Therefore, the number of bag of pretzel be 8 while the number of bag of crackers be 4.
