Question

Factor 16x2 + 121 over the set of complex numbers.
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Answer 1

Answer:

(4x - 11i)(4x -+11i)

Step-by-step explanation:

Factor as a difference of squares

a² - b² = (a - b)(a + b)

note that i² = - 1

Given

16x² + 121

= (4x)² - (11i)²

= (4x - 11i)(4x + 11i)