Question

what is the 9th term of the geometric sequence 5 -25 125

Answer 1

Answer:

Step-by-step explanation:

hello :

the n-ieme term is : An=A1×r^(n-1)

A1 the first term       r : the common ratio

in this exercice : A1 =5       r = 125/-25=-25/5 = - 5         n = 9

A9=5×(-5)^(9-1) = 5×5^8 = 5^9     because :   ((-5)^(8)= 5^8)