Answer:
Radius of the cone = [tex]\sqrt{51.12}feet[/tex]
Step-by-step explanation:
Volume of a cone:
[tex]\pi *r^2*\frac{h}{3}[/tex]
For volume=321 feet^3 and
Height= 6 feet
[tex]321=\pi *r^2*\frac{h}{3}[/tex]
As, [tex]\pi =\frac{22}{7}=3.14[/tex]
So ,
[tex]321=3.14*r^2*\frac{6}{3}[/tex]
[tex]321=3.14*2*r^2\\\\321=6.28*r^2\\\\r^2=321/6.28\\\\r^2=51.12\\\\r=\sqrt{51.12}feet[/tex]
So, the Radius of the cone is [tex]\sqrt{51.12}feet[/tex]
