Answer:
Power drawn in this circuit is 1100 W
Explanation:
As we know that electrical power is defined as the rate of electrical energy drawn
so we can say it is given as
[tex]P = \frac{dQ}{dt}[/tex]
here we know that
[tex]Q = qV[/tex]
here we have
[tex]P = V\frac{dq}{dt}[/tex]
[tex]P = i V[/tex]
[tex]P = 10 (110)[/tex]
[tex]P = 1100 W[/tex]