Use normal approximation to estimate the probability of passing a true/false test of 50 questions if the minimum passing grade is 60% and all responses are random guesses.

Respuesta :

Answer:

7.93% probability of passing the test.

Step-by-step explanation:

We use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].

Guessed true/false question.

Each have two options, one of which is correct, so [tex]p = \frac{1}{2} = 0.5[/tex]

50 questions

This means that [tex]n = 50[/tex]

So

[tex]\mu = E(X) = np = 50*0.5 = 25[/tex]

[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{50*0.5*0.5} = 3.5356[/tex]

Probability of passing a true/false test of 50 questions if the minimum passing grade is 60% and all responses are random guesses.

This probability is 1 subtracted by the pvalue of Z when X = 0.6*50 = 30. So

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{30 - 25}{3.5356}[/tex]

[tex]Z = 1.41[/tex]

[tex]Z = 1.41[/tex] has a pvalue of 0.9207

1 - 0.9207 = 0.0793

7.93% probability of passing the test.

The probability of passing the true/false test of 50 questions is 0.0793

How to determine the probability?

For a true or false question, the probability of getting an answer is:

[tex]p = 0.5[/tex]

In a test of 50 questions, the mean and the standard deviation are:

[tex]\bar x = np = 50 * 0.5 = 25[/tex]

[tex]\sigma= \sqrt{np(1-p)} = \sqrt{50 * 0.5 * (1 - 0.5)} = 3.54[/tex]

Since the minimum passing grade is 60%, the minimum question is:

[tex]x = 60\% * 50 = 30[/tex]

Next, we calculate the z-score

[tex]z = \frac{x - \bar x}{\sigma}[/tex]

So, we have:

[tex]z = \frac{30 - 25}{3.54}[/tex]

[tex]z = 1.41[/tex]

Next, calculate the p value

[tex]p =1- P(z = 1.41)[/tex]

Using the z tables of probability, we have:

[tex]p = 1-0.9207[/tex]

[tex]p = 0.0793[/tex]

Hence, the probability of passing the true/false test of 50 questions is 0.0793

Read more about probability at:

https://brainly.com/question/25870256

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