Answer:
B
Step-by-step explanation:
well by rotating ΔABC by 60*(degrees) about A , such that in ΔA'B'C,B =C'
you can see that ΔAPP' is equilateral side length 1, meaning that <APP' =60*
you can also see that ΔCPP' is a 30- 60- 90 right angle also meaning that <CPP' =60* now,by adding the two together you see that < ACP =120* now you can also use the law of cosins and soooo
s2=(AP)2+(CP)2-2(AP)(CP)cos120*
s2=1+4-2(1)(2)cos120*
s2=5-4 (-1over2)
s=[tex]\sqrt{x} 5+2\\[/tex]
7
so b is your answer hope this helped
