Respuesta :

Ben

[tex]\huge\boxed{x=2;\ y=-1}[/tex]

[tex]\left\{{{2x-5y=9}\atop{3x+4y=2}}\right[/tex]

First, we will solve the second equation for [tex]x[/tex]. Subtract [tex]4y[/tex] from both sides of the second equation.

[tex]3x=2-4y[/tex]

Divide both sides of the second equation by [tex]3[/tex].

[tex]x=\frac{2}{3}-\frac{4}{3}y[/tex]

[tex]\left\{{{2x-5y=9}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right[/tex]

Substitute the value of [tex]x[/tex] from the second equation into the first.

[tex]\left\{{{2(\frac{2}{3}-\frac{4}{3}y)-5y=9}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right[/tex]

[tex]2(\frac{2}{3}-\frac{4}{3}y)-5y=9[/tex]

We will solve the first equation for [tex]y[/tex].

Distribute the [tex]2[/tex] to the [tex](\frac{2}{3}-\frac{4}{3}y)[/tex].

[tex]\frac{4}{3}-\frac{8}{3}y-5y=9[/tex]

Combine the like terms.

[tex]\frac{4}{3}-\frac{23}{3}y=9[/tex]

Add [tex]\frac{4}{3}[/tex] on both sides.

[tex]-\frac{23}{3}y=9-\frac{4}{3}[/tex]

[tex]-\frac{23}{3}y=\frac{23}{3}[/tex]

Divide both sides by [tex]\frac{23}{3}[/tex].

[tex]-y=1[/tex]

Multiply both sides by [tex]-1[/tex].

[tex]y=\boxed{-1}[/tex]

Substitute the value of [tex]y[/tex] into the second equation.

[tex]\left\{{{y=-1}\atop{x=\frac{2}{3}-\frac{4}{3}y}}\right[/tex]

[tex]x=\frac{2}{3}-\frac{4}{3}*-1[/tex]

Multiply.

[tex]x=\frac{2}{3}+\frac{4}{3}[/tex]

Add.

[tex]x=\frac{6}{3}[/tex]

[tex]x=\boxed{2}[/tex]

Answer:

x = 2

y= -1

Step-by-step explanation:

to solve this simultaneous equation, using substitution method, we say

let

2x-5y=9 ....................... equation 1

3x+4y=2....................... equation 2

from equation 2

3x+4y=2....................... equation 2

3x = 2-4y

divide both sides by 3

3x/3 = ( 2-4y)/3

x = ( 2-4y)/3 ......................... equation 3

substitute for x , x = ( 2-4y)/3in equation 3 in equation 1

2x-5y=9 ....................... equation 1

2(2-4y)/3 - 5y = 9

4 -8y/3 - 5y = 9

multiply through by 3

3 [(4-8y)/3] - 3(5y) = 3(9)

4 - 8y - 15y = 27

-23y = 27-4

-23y =23

divide both sides by the coefficient of y which is -23

-23y/-23 = 23/-23

y = -1

put y = -1 in equation 3

x = ( 2-4y)/3 ......................... equation 3

x = (2 -4(-1)]/3

x = (2 +4)/3

x = 6/3

x = 2

therefore the value of x and y is 2 and -1 respectively

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