Question

Find the limit: $\lim_{x \to \ 3 }$ $\frac{x^3 +27}{x+3}$

Answer 1

 

$\displaystyle\bf\\\lim_{x\to3}\frac{x^3+27}{x+3}=\frac{3^3+27}{3+3}=\frac{27+27}{3+3}=\frac{54}{6}=\boxed{\bf9}$

 

 

Answer 2

Answer:

Step-by-step explanation:

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