Answer:.
Required velocity = 6.26ms^-1
Explanation:
Given,
Distance, s = 450m
Time, t = 2 sec
Step 1. We obtain the distance covered within the given time under gravitational acceleration, g = 9.8ms^-2
S = ut + (1/2)gt^2. :; u = 0
: S = (1/2)gt^2
=(1/2) (9.8)(2^2)
= 19.6m
Step 2 :
We obtain the velocity using the formula.
V^2 = u^2 + 2gs.
Where u is initial velocity, v is final/ required velocity
Again u = 0
: V^2 = 2 (9.8)(19.6)
= 39.2
: V = 6.26ms^-1
