Question

What is the ph of a solution with a [OH] of 3.31x10 -7 M

Answer 1

Answer: The pH of the solution is 7.52

Explanation:

To calculate the pOH of the solution, we use the equation:

$pOH=-\log[OH^-]$

We are given:

$[OH^-]=3.31\times 10^{-7}$

Putting values in above equation, we get:

$pOH=-\log (3.31\times 10^{-7})\\\\pOH=6.48$

To calculate pH of the solution, we use the equation:

$pH+pOH=14\\\\pH=14-6.48=7.52$

Hence, the pH of the solution is 7.52