Question

Mickey, a daredevil mouse of mass 0.0187 kg, 0.0187 kg, is attempting to become the world's first "mouse cannonball." He is loaded into a spring‑powered gun pointing up at some angle and is shot into the air. The gun's spring has a force constant of 60.1 N/m 60.1 N/m and is initially compressed a distance of 0.131 m 0.131 m from its relaxed position. If Mickey has a constant horizontal speed of 2.25 m/s 2.25 m/s while he is flying through the air, how high h h above his initial location in the gun does Mickey soar? Assume g = 9.81 m/s 2 .

Answer 1

Answer:

Explanation:

Velocity of projection can be calculated from conservation of mechanical energy .

Stored potential energy of spring = kinetic energy of mouse

= 1/2 k x ² = 1/2 m v²

k is spring force , x is compression , m is mass of mouse and v is its velocity

60.1 x .131² = .0187 x v²

v² = 55.15

v = 7.42 m / s

If angle of projection be θ

Given

7.42 cosθ = 2.25

θ = 72 degree .

maximum height achieved

v² sin²θ / 2g

= (55.15 / 2 x 9.8) x sin²72

= 2.54 m .  

Answer 2

Answer:

2.54 m i think i had this one

Explanation: