Question

A circular room has a radius of 3.0 m. An 80 kg man stands with his back against the wall. The room then spins so the man is moving in a circle. How fast does the man have to be moving so that the normal force from the wall on his back is equal to his weight

Answer 1

Answer:

Explanation:

Given:

Mass, M = 80 kg

Acceleration due to gravity, g = 9.81 m/s^2

Radius, R = 3 m

Normal force, N = M × a

= M × v/t

Centripetal force, Fc = M × v^2/R

Fc = N

a = v^2/R

v = sqrt(9.81 × 3)

= 5.425 m/s

v = w × R

w = angular velocity

w = 5.425/3

= 1.808 rad/s