Question

4.Hawkeye draws his compound bow and shoots an arrow. The 23 g arrow leaves the bow with a velocity of 88 m/s. The power stroke of the bow is 57 cm; that is, the bowstring exerts force on the arrow through a displacement of 57 cm. The peak draw weight of the bow is 312 N. (This is the maximum force that the archer has to exert on the bowstri

Answer 1

Answer:

The kinetic energy of the arrow after release is 89.056 J.

Explanation:

Given that,

Mass of arrow, m = 23 g = 0.023 kg

Velocity of the arrow, v = 88 m/s

The power stroke of the bow is 57 cm. The peak draw weight of the bow is 312 N. We need to find the kinetic energy does the arrow have after release. So, it is given by :

$K=\dfrac{1}{2}mv^2\\\\K=\dfrac{1}{2}\times 0.023\times 88^2\\\\K=89.056\ J$

So, the kinetic energy of the arrow after release is 89.056 J. Hence, this is the required solution.