Question

Jerome and Noah are walking on a trail in the park. Jerome starts at 50 meters east of the park gate and walks away from the gate at the speed of 1.11 meters per second. Noah starts at 57 meters east of the park gate and walks away from the gate at the speed of 0.97 meters per second in the same direction as Jerome. After walking for how many seconds will Noah and Jerome be side-by-side on the trail?

Answer 1

Answer:

50 seconds.

Step-by-step explanation:

Given:

Jerome starts at 50 meters east of the park gate

Noah starts at 57 meters east of the park gate

Walking speed of Jerome =  1.11 meters per second.

Walking speed of Noah = 0.97 meters per second

Both are walking in the same direction.

Question asked:

After walking for how many seconds will Noah and Jerome be side-by-side on the trail?

Solution:

Let time = $t$

It is given that Jerome starts at 50 meters east of the park gate and Noah starts at 57 meters east of the park gate means distance covered by Jerome will be 7 meter more than Noah.

Distance covered by Jerome - Distance covered by Noah = 7

$speed\times time - speed\times time = 7$

$1.11\times t-0.97\times t = 7\\1.11 t-0.97 t = 7\\0.14t=7$

Dividing both sides by 7

$t=50\ seconds$

Thus, after walking 50 seconds Noah and Jerome will be side-by-side on the trail.